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Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + O2(g) → 2 NO2(g) [NO]i (M) [O2]i (M) Initial Rate (M-1s-1) 0) 030 0.0055 8.55 × 10-3 0) 030 0.0110 1.71 × 10-2 0) 060 0.0055 3.42 × 10-2


A) Rate = 57 M-1s-1[NO][O2]
B) Rate = 3.8 M-1/2s-1[NO][O2]1/2
C) Rate = 3.1 × 105 M-3s-1[NO]2[O2]2
D) Rate = 1.7 × 103 M-2s-1[NO]2[O2]
E) Rate = 9.4 × 103 M-2s-1[NO][O2]2

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The rate constant for a second-order reaction is 0.54 M-1s-1.What is the half-life of this reaction if the initial concentration is 0.33 M?


A) 0.089 s
B) 1.8 s
C) 0.31 s
D) 5.6 s
E) 1.3 s

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What are the units of k in the following rate law? Rate = k[X]2


A) Ms-1
B) Ms
C) M-1s-1
D) M-2s-1
E) M2s-1

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Define activation energy.

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The activation energy is an en...

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A particular first-order reaction has a rate constant of 1.35 × A particular first-order reaction has a rate constant of 1.35 ×     at 25.0°C.What is the magnitude of k at   A)  9.56 × 10<sup>3</sup> s<sup>-1</sup> B)  2.85 × 10<sup>4</sup> s<sup>-1</sup> C)  576 s<sup>-1</sup> D)  4.33 × 10<sup>87</sup> s<sup>-1</sup> E)  1.36 ×   s<sup>-1</sup> A particular first-order reaction has a rate constant of 1.35 ×     at 25.0°C.What is the magnitude of k at   A)  9.56 × 10<sup>3</sup> s<sup>-1</sup> B)  2.85 × 10<sup>4</sup> s<sup>-1</sup> C)  576 s<sup>-1</sup> D)  4.33 × 10<sup>87</sup> s<sup>-1</sup> E)  1.36 ×   s<sup>-1</sup> at 25.0°C.What is the magnitude of k at A particular first-order reaction has a rate constant of 1.35 ×     at 25.0°C.What is the magnitude of k at   A)  9.56 × 10<sup>3</sup> s<sup>-1</sup> B)  2.85 × 10<sup>4</sup> s<sup>-1</sup> C)  576 s<sup>-1</sup> D)  4.33 × 10<sup>87</sup> s<sup>-1</sup> E)  1.36 ×   s<sup>-1</sup>


A) 9.56 × 103 s-1
B) 2.85 × 104 s-1
C) 576 s-1
D) 4.33 × 1087 s-1
E) 1.36 × A particular first-order reaction has a rate constant of 1.35 ×     at 25.0°C.What is the magnitude of k at   A)  9.56 × 10<sup>3</sup> s<sup>-1</sup> B)  2.85 × 10<sup>4</sup> s<sup>-1</sup> C)  576 s<sup>-1</sup> D)  4.33 × 10<sup>87</sup> s<sup>-1</sup> E)  1.36 ×   s<sup>-1</sup> s-1

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For a certain reaction,a plot of ln [A] vs.time gives a straight line with a slope of -1.46 s-1 and a y-intercept of 4.30.What is the order of the reaction?


A) zeroth-order
B) first-order
C) second-order
D) third-order
E) not enough information is given to solve the problem

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The elementary reaction The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 (g) → 2NO(g) + The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 (g) is second order in The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 and the rate constant at 501 K is 7.93 × 10-3 The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 .The reaction half-life at this temperature when The elementary reaction   (g) → 2NO(g) +   (g)  is second order in   and the rate constant at 501 K is 7.93 × 10<sup>-3</sup>     .The reaction half-life at this temperature when   = 0.45 M is ________ s. A)  3.6 × 10<sup>-3</sup> B)  0.011 C)  126 D)  87 E)  280 = 0.45 M is ________ s.


A) 3.6 × 10-3
B) 0.011
C) 126
D) 87
E) 280

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Give the characteristic of a second order reaction having only one reactant.


A) The rate of the reaction is not proportional to the concentration of the reactant.
B) The rate of the reaction is proportional to the square of the concentration of the reactant.
C) The rate of the reaction is proportional to the square root of the concentration of the reactant.
D) The rate of the reaction is proportional to the natural logarithm of the concentration of the reactant.
E) The rate of the reaction is directly proportional to the concentration of the reactant.

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What is the overall order of the following reaction,given the rate law? 2 X + 3 Y → 2 Z Rate = k[X]1[Y]2


A) 3rd order
B) 5th order
C) 2nd order
D) 1st order
E) 0th order

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Which of the following represents the integrated rate law for a first-order reaction?


A) Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA = - kt
B) Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA - Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA = kt
C) [A]t - [A]o = - kt
D) k = Ae(-Ea/RT)
E) Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA = Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA Which of the following represents the integrated rate law for a first-order reaction? A)    = - kt B)    -   = kt C)  [A]<sub>t</sub> - [A]<sub>o</sub> = - kt D)  k = Ae<sup>(-Ea/RT) </sup> E)    =     + lnA + lnA

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Give the characteristic of a zero order reaction having only one reactant.


A) The rate of the reaction is not proportional to the concentration of the reactant.
B) The rate of the reaction is proportional to the square of the concentration of the reactant.
C) The rate of the reaction is proportional to the square root of the concentration of the reactant.
D) The rate of the reaction is proportional to the natural logarithm of the concentration of the reactant.
E) The rate of the reaction is directly proportional to the concentration of the reactant.

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What are the units of k in the following rate law? Rate = k[X][Y]1/2


A) M/s
B) M-1s-1
C) M1/2s-1
D) M-1/2s-1
E) M-1s-1/2

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The rate constant for a first-order reaction is 0.54 s-1.What is the half-life of this reaction if the initial concentration is 0.33 M?


A) 0.089 s
B) 1.8 s
C) 0.31 s
D) 5.6 s
E) 1.3 s

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What is a catalyst and what function does it serve?

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A catalyst is a substance that is not us...

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Write a balanced reaction for which the following rate relationships are TRUE. Rate = Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O = Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O = - Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O


A) Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O N2 + O2 Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O N2O
B) 2 N2O → 2 N2 + O2
C) N2O → N2 + 2 O2
D) Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O N2O → Write a balanced reaction for which the following rate relationships are TRUE. Rate =     =   = -     A)    N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub> <sub> </sub>   N<sub>2</sub>O B)  2 N<sub>2</sub>O → 2 N<sub>2</sub> + O<sub>2</sub> C)  N<sub>2</sub>O → N<sub>2</sub> + 2 O<sub>2</sub> D)    N<sub>2</sub>O →   N<sub>2</sub> + O<sub>2</sub> E)  2 N<sub>2</sub> + O<sub>2 </sub>→<sub> </sub>2 N<sub>2</sub>O N2 + O2
E) 2 N2 + O2 2 N2O

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The first-order decomposition of ammonium nitrate has a rate constant of 0.110 min-1.If the initial concentration is 0.551 M,what is the concentration after 38.5 min?


A) 0.0372 M
B) 7.98 × 10-3 M
C) 0.513 M
D) 0.221 M
E) 0.143 M

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The combustion of ethylene proceeds by the reaction C2H4(g) + 3O2(g) →2CO2(g) + 2H2O(g) When the rate of disappearance of O2 is 0.28 M s-1,the rate of appearance of CO2 is ________ M s-1.


A) 0.19
B) 0.093
C) 0.84
D) 0.42
E) 0.56

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In the hydrogenation of double bonds,a catalyst is needed.In the first step,the reactants must come into contact with a metal surface.This step is known as


A) adsorption.
B) diffusion.
C) reaction.
D) desorption.
E) none of the above.

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The first-order decomposition of N2O5 at 328 K has a rate constant of 1.70 × 10-3 s-1.If the initial concentration of N2O5 is 2.88 M,what is the concentration of N2O5 after 12.5 minutes?


A) 0.124 M
B) 0.805 M
C) 2.82 M
D) 0.355 M
E) 0.174 M

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A reaction occurs via the following sequence of elementary steps.What is the rate law based on this reaction mechanism? 1st step: A ⇌ B very fast 2nd step: B + C → D slow 3rd step: D → 2E fast


A) rate = k [E]2
B) rate = k [B] [C]
C) rate = k [A] [B]
D) rate = k [D]
E) rate = k [A] [C]

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