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Given the heat of formation of the following compounds: Given the heat of formation of the following compounds:   What is the value of Δ<sub>r</sub>H° for the reaction: CH<sub>3</sub>OH(l) + 3/2 O<sub>2</sub>(g) → CO<sub>2</sub>(g) + 2 H<sub>2</sub>O(l)  A) -440.8 kJ/mol B) -416.9 kJ/mol C) -1203.9 kJ/mol D) -346.2 kJ/mol E) -726.7 kJ/mol What is the value of ΔrH° for the reaction: CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l)


A) -440.8 kJ/mol
B) -416.9 kJ/mol
C) -1203.9 kJ/mol
D) -346.2 kJ/mol
E) -726.7 kJ/mol

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From the following thermochemical equations,calculate ΔrH° for the reaction: SO2(g) + NO2(g) → SO3(g) + NO(g) 2 SO2(g) + O2(g) → 2 SO3(g) ΔrH° = -197.8 kJ/mol 2 NO(g) + O2(g) → 2 NO2(g) ΔrH° = -114.14 kJ/mol


A) -83.66 kJ /mol
B) -311.9 kJ/mol
C) +155.9 kJ/mol
D) -155.9 kJ/mol
E) -41.83 kJ/mol

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The specific heat capacity of liquid mercury is 0.14 J g-1k-1.How many joules of heat are needed to raise the temperature of 5.00 g of mercury from 15.0 °C to 36.5 °C?


A) 7.7 × 102 J
B) 15 J
C) 36 J
D) 0.0013 J
E) 1.7 J

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The complete combustion of propane,C3H8(g) ,is represented by the equation: C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l) ΔrH° = -2220 kJ /mol How much heat is evolved in the complete combustion of 12.5 L C3H8(g) at 25 °C and 790 mmHg?


A) 8.27 × 104 kJ
B) 1.41 × 104 kJ
C) 653 kJ
D) 168 kJ
E) 1180 kJ

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Calculate ΔfH° of octane,C8H18(l) ,given the enthalpy of combustion of octane to CO2(g) and H2O(l) ,-5471 kJ/mol,and the standard enthalpies of formation of CO2(g) and H2O(l) ,-393.5 kJ/mol and -285.8 kJ/mol,respectively.


A) -249.2 kJ/mol
B) +4792 kJ/mol
C) +249.2 kJ/mol
D) -4792 kJ/mol

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A closed system can exchange matter but not energy with the surroundings.

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Compute ΔrH° for the following reaction.The value of ΔfH° in kJ/mol is given below each species: Compute Δ<sub>r</sub>H° for the following reaction.The value of Δ<sub>f</sub>H° in kJ/mol is given below each species:   A) -688.6 kJ/mol B) -200.1 kJ/mol C) -74.9 kJ/mol D) -1000.6 kJ/mol E) -900.3 kJ/mol


A) -688.6 kJ/mol
B) -200.1 kJ/mol
C) -74.9 kJ/mol
D) -1000.6 kJ/mol
E) -900.3 kJ/mol

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Determine the enthalpy change in the following equation: Cl2(g) + H2O(l) → 2 HCl(g) + 1/2 O2(g) ΔfH° H2O(l) = -285.8 kJ/mol ΔfH° HCl(g) = -92.31 kJ/mol


A) 193.5 kJ/mol
B) -470.4 kJ/mol
C) 470.4 kJ/mol
D) 101.2 kJ/mol
E) -101.2 kJ/mol

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Choose the INCORRECT statement.


A) Kinetic energy is the energy of motion.
B) Potential energy is energy in action.
C) Heat is energy transferred as a result of a temperature difference.
D) Pressure-volume work is calculated by w = −PΔV.
E) Heat is transferred from a warmer body to a colder one.

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Kinetic energy is the energy of motion.

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For the reaction H2(g) + 1/2 O2(g) → H2O(g) ΔrH° = -241.8 kJ/mol, What mass of H2(g) is required to liberate 1.00 × 103 kJ of heat?


A) 66.2 g
B) 4.17 g
C) 8.34 g
D) 2.05 g
E) 16.7 g

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A 5.00 g sample of copper metal at 25.0 °C is heated by the addition of 96.0 J of energy.The final temperature of the copper is ________ °C.The specific heat capacity of copper is A 5.00 g sample of copper metal at 25.0 °C is heated by the addition of 96.0 J of energy.The final temperature of the copper is ________ °C.The specific heat capacity of copper is   A) 32.3 B) 25.0 C) 25.5 D) 75.5 E) 50.5


A) 32.3
B) 25.0
C) 25.5
D) 75.5
E) 50.5

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Coal contains an impurity that reacts with oxygen during the combustion process,producing oxides that are major environmental pollutants.This impurity is:


A) acid rain
B) nitrogen
C) sulfur
D) carbon dioxide
E) peat

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The standard enthalpy for diamond and graphite are the same value.

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Calculate the work,w,gained or lost by the system when a gas expands from 15 L to 40 L against a constant external pressure of 1.5199 bar.


A) -6.1 kJ
B) -3.8 kJ
C) +3.8 kJ
D) +6.1 kJ

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To have a standard enthalpy of formation referenced to 0 J/mol,the substance must: I.be a simple substance (chemical element) II.be in its most stable form III.be under 1 bar of pressure IV.have a concentration of 1.0000 M


A) I,III,IV
B) I,II,III
C) II,IV
D) I,III
E) II,III,IV

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The standard enthalpy of formation of NH4Cl(s) is -315.4 kJ/mol.The equation that describes this △fH° is:


A) NH4+(aq) + Cl-(aq) → NH4Cl(s)
B) 1/2 N2(g) + 2 H2(g) + 1/2 Cl2(g) → NH4Cl(s)
C) N2(g) + H2(g) + Cl2(g) → 2 NH4Cl(s)
D) 1/2 N2(g) + 1/2 Cl2(g) + 1/2 H2(g) → NH4Cl(s)
E) N2(g) + Cl2(g) + 4 H2(g) → 2 NH4Cl(s)

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Consider the reaction: Consider the reaction:    Compute Δ<sub>r</sub>H° for this reaction. A) -994.67 kJ/mol B) 23.05 kJ /mol C) -23.05 kJ /mol D) 69.25 kJ /mol E) -69.25 kJ/mol Compute ΔrH° for this reaction.


A) -994.67 kJ/mol
B) 23.05 kJ /mol
C) -23.05 kJ /mol
D) 69.25 kJ /mol
E) -69.25 kJ/mol

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Oxygen gas at 34.5 °C expands from 34.5 L to 45.7 L against a constant pressure of 750 mmHg.What is the work done in joules by the system?


A) 1.12 × 103 J
B) -1.12 × 103 J
C) 9.09 × 104 J
D) -9.09 × 104 J
E) 4.55 × 103 J

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Calculate ΔU for a system that loses 475 kJ of heat and does 155 kJ of expansion work on the surroundings.


A) -630 kJ
B) -320 kJ
C) +630 kJ
D) +320 kJ

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